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Supersymmetry. Theory, Experiment, and Cosmology

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Exercises 489

in loop momenta. This is the dimensional reduction scheme (DR corresponding to

M S) [85, 340].

Since DR is compatible with supersymmetry, we have as expected g = gˆ in this

scheme. On the other hand,

 

 

 

 

 

 

 

 

g2

 

g

 

= g

 

1 −

 

C2(G) ,

(E.31)

M S

DR

96π2

 

 

 

 

 

g2

 

gˆ

 

= g

 

1 +

 

(C2(G) − C2(R)) ,

(E.32)

M S

DR

96π2

where C2(G) is defined in (9.18) and C2(R)δij = a (tata)ij

(R is the representation

of the chiral supermultiplet of (E.30) under the gauge group G).

#

 

We also note the following relation for the gaugino mass parameters:

 

 

 

g2

 

MλM S

= MλDR

1 +

 

C2(G) .

(E.33)

16π2

A complication arises in dimensional reduction: from the point of view of D dimensions, local invariance applies only to the components Aa0 , · · · , AaD−1 of the vector fields. The remaining 2 components AaD, · · · , Aa3 are scalars under the Lorentz group in D dimensions: they are called -scalars. They induce additional renormalization counter terms and care must be taken at higher orders to take these fields into account.

Finally, we note that, in the DR scheme, heavy thresholds e ects are very simply taken into account in renormalization group analyses: they are properly described by a simple step function localized precisely at the mass of the heavy field [7].

Exercises

Exercise 1 Show that ξ1 defined in (E.24) satisfies

 

2 dξ1

2

 

 

8π

 

 

= −b1g1

ξ1

(E.34)

 

dt

and solve this equation.

Hints: The equations for the first two families are read from (E.19)–(E.23) by neglecting the Yukawa couplings.

Solution: ξ1(µ) = g12(µ)ξ1(µ0)/g12(µ0).

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