- •132. How many 5-place telephone numbers are there if the digit “0” is not used on the first place? 90000
- •159. It is known that 10% of all radio lamps are non-standard. Find the probability that there will be no more than 1 non-standard lamp among 4 randomly taken radio lamps. 0,6561
- •164. We say that a discrete random variable X is distributed under Poisson law with parameter if
- •167. Dispersion of a constant c is 0
- •191. The mathematical expectation of a continuous random variable X of which possible values belong to an interval [a, b] is
- •Integral ot a do b X φ(X)ds
- •193. A distribution of probabilities of a continuous random variable X is exponential if it is described by the density
- •194. A random variable X is normally distributed with parameters a and 2 if its density f(X) is:
159. It is known that 10% of all radio lamps are non-standard. Find the probability that there will be no more than 1 non-standard lamp among 4 randomly taken radio lamps. 0,6561
160. 8 buyers came in a shop. What is the probability that 3 of them will do shopping if the probability to make purchase for each buyer is equal to 0,3? 0,254
161. Distribution of a discrete random variable X is given by the table
X |
-2 |
-1 |
0 |
1 |
Р |
1/4 |
¼ |
¼ |
1/4 |
Find the mathematical expectation M(X). -0,5
162. Distribution of a discrete random variable X is given by the table
X |
-2 |
-1 |
0 |
1 |
Р |
1/4 |
¼ |
¼ |
1/4 |
Find the dispersion D(X). 0,25
163.
We say that a discrete random variable X is distributed under a
binomial law if P(X=K)
=
164. We say that a discrete random variable X is distributed under Poisson law with parameter if
165. We say that a discrete random variable X is distributed under a geometrical law if pq^n-1
166. Dispersion of a discrete random variable X is M(X^2)-[M(X)]^2 or M(X-M(X))^2
167. Dispersion of a constant c is 0
168. The law of distribution of a discrete random variable X is given. Find Y.
|
-1 |
2 |
3 |
|
0.2 |
0.5 |
Y |
169. The law of distribution of a discrete random variable X is given, M (X) = 6. Find x1. 2
|
x1 |
7 |
8 |
|
0.3 |
p2 |
0.5 |
170. Distribution of a discrete random variable X is given. What is M(X) equal to? 3,9
|
3 |
5 |
4 |
|
0.4 |
0.3 |
0.3 |
171. A discrete random variable X is given by the law of distribution:
X |
-5 |
0 |
5 |
P |
0,2 |
0,6 |
0,2 |
Then the mathematical expectation M(X) is equal to: 0
172. A discrete random variable X is given by the law of distribution:
X |
x1 |
x2 |
x3 |
x4 |
Р |
0,2 |
0,1 |
р3 |
0.4 |
Then the probability р3 is equal to: 0,3
173. Mathematical expectation of a normally distributed random variable X is 3, and mean square deviation is 2. Write the density of distribution X. f(x) = 1/2√2П*e^-(x-3)^2/8
174. Pairwise incompatible events A1, A2 and A3 form a complete group, and P(A1) = 0,3; P(A3) = 0,4. Then P(A2) is equal to: 0,3
175. For an event - landing two heads at tossing two coins - the opposite event is: at least one tail
176.
A random variable X(–
,
)
has a normal density of distribution
.
Find the value of parameter . 2
177. Show the Bernoulli formula
178. Show the mathematical expectation of a discrete random variable X: M(X) = Zxipi
179. An improper integral of density of distribution in limits from – till is equal to integral ot minus besk do plus besk φ (x)dx=1
180. Mathematical expectation of a continuous random variable X of which possible values belong to the entire axis OX is determined by the equality M(x) = integral ot minus besk do plus besk x φ(x)dx
181. Dispersion of a continuous random variable X of which possible values belong to the entire axis OX is defined by the equality
D(X) = integral ot minus besk do plus besk (x-a)^2 φ(x)
182. The random variable X is given by an integral function of distribution:
Find the probability of hit of the random variable X in the interval (0; 1): 1/3
183. Show one of true properties of mathematical expectation (C is a constant) M( C ) = C
184. Let M(X) = 2. Find M(X – 2). 0
185. Let M(X) = 2. Find M(2X). 4
186. Let D(X) = 2. Then D(X – 2) is equal to 2
187. Let D(X) = 3. Then D(2X) is equal to 12
188. Let f(x) be a density of distribution of a continuous random variable X. Then the function of distribution is:
F(X) = integral ot minus besk do x f(t)dt
189. Mean square deviation of a random variable X is determined by the following formula √Ds
190. A discrete random variable X is given by the law of distribution:
-
X
x1
x2
x3
x4
Р
р1
0,2
0,1
0,5
Then the probability р1 is equal to: 0,2
